Solve the circuit and find the power of sources:

, , , , , .

Solution:

There are three meshes in the circuit. So, we need to assign three mesh currents. It is better to have all the mesh currents loop in the same direction (usually clockwise) to prevent errors when writing out the equations.

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# Monthly Archives: September 2013

# Solve By Source Definitions, KCL and KVL

Find the voltage across the current source and the current passing through the voltage source.

Assume that , , , ,, ,

Solution

is in series with the current source; therefore, the same current passing through it as the current source:

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# Find Voltage Using Voltage Division Rule

Determine voltage across and using voltage division rule.

Assume that

, , , and

Solution:

Please note that the voltage division rule cannot be directly applied. This is to say that:

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# Find currents using KVL

Find resistor currents using KVL.

Solution:

and are parallel. So the voltage across is equal to . This can be also calculated using KVL in the left hand side loop:

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