# Problem

Find $I_x$ and $I_y$ :

# Solution

Three resistors are in series and their equivalent, $6\Omega$, is parallel with the voltage source. So, according to the Ohm's law: $I_y=-\frac{6V}{6 \Omega}=-1 A$. The negative sign comes from the direction $I_y$.
Applying KCL at the bottom node:
$-(-2A)+I_x+I_y=0 \rightarrow I_x=-1 A$.
The lucky winner of the Electrical Circuits Contest #1 is Kunal Marwaha from UC Berkeley. I would like to say thank you to all participants and I am thinking of holding contest #2 soon. Kunal, congratulations and soon you will receive the prize by Paypal.

# Electrical Circuit Contest - Win \$10!

What's up? We are going to have fun!
This is our first contest for electrical circuits. Solve the problem, submit your answers and cross your fingers to be the lucky winner!

## Problem

Find $I_x$ and $I_y$: