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Monthly Archives: September 2013

Mesh Analysis – Supermesh

The mesh analysis used to solve the circuit which has a supermesh. After solving the circuit, power of sources determined.

Posted byYazSeptember 27, 2013August 21, 2019Posted inResistive CircuitsTags: Current Source, Independent Sources, mesh, Mesh_Analysis, Power, power calculation, Resistor, Source, supermesh15 Comments on Mesh Analysis – Supermesh

Solve By Source Definitions, KCL and KVL

A DC resistive circuit consisting of one voltage source and one current source and three resistors is solved using source definition, KCL and KVL.

Posted byYazSeptember 27, 2013August 21, 2019Posted inResistive CircuitsTags: Current Source, KCL, KVL, KVL_KCL, Ohm, Ohm's law, Source, Voltage Source5 Comments on Solve By Source Definitions, KCL and KVL

Find Voltage Using Voltage Division Rule

Determine voltage across and using voltage division rule. Assume that , , , and Solution: Please note that the voltage division rule cannot be directly applied. This is to say that:

Posted byYazSeptember 26, 2013September 26, 2013Posted inResistive CircuitsTags: circuit reduction, Thévenin, thevenin equivalent circuit, voltage divider, voltage division rule, Voltage Source10 Comments on Find Voltage Using Voltage Division Rule

Find currents using KVL

Resistive Circuit

A simple circuit with two voltage sources and two resistors solved using only KVL.

Posted byYazSeptember 26, 2013August 21, 2019Posted inResistive CircuitsTags: Independent Sources, KVL, KVL_KCL, linear, Ohm's law, Source13 Comments on Find currents using KVL

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