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Monthly Archives: October 2013

Winner of Electrical Circuits Contest #1

Problem Find and : Solution Three resistors are in series and their equivalent, , is parallel with the voltage source. So, according to the Ohm’s law: . The negative sign comes from the direction . Applying KCL at the bottom node: . The lucky winner of the Electrical Circuits Contest #1 is Kunal Marwaha from […]

Posted byYazOctober 21, 2013December 14, 2014Posted inElectrical Circuits Contests8 Comments on Winner of Electrical Circuits Contest #1

Find Equivalent Impedance – AC Steady State Analysis

Determine the driving-point impedance of the network at a frequency of kHz: Solution Lets first find impedance of elements one by one: Resistor The resistor impedance is purely real and independent of frequency.

Posted byYazOctober 19, 2013April 18, 2015Posted inAC Steady State AnalysisTags: AC, AC steady State Analysis, capacitor, impedance, Steady State7 Comments on Find Equivalent Impedance – AC Steady State Analysis

Electrical Circuit Contest – Win $10!

What’s up? We are going to have fun! This is our first contest for electrical circuits. Solve the problem, submit your answers and cross your fingers to be the lucky winner! Problem Find and :

Posted byYazOctober 15, 2013October 20, 2013Posted inElectrical Circuits ContestsTags: contest, Independent Sources, Source10 Comments on Electrical Circuit Contest – Win $10!

Superposition method – Circuit with two sources

Finding current by using superposition method. There are two independent sources, so we need to turn them off one by one and calculate their contributions.

Posted byYazOctober 15, 2013August 21, 2019Posted inResistive CircuitsTags: KCL, Superposition, Superposition Method, Superposition_Method, Turning sources off23 Comments on Superposition method – Circuit with two sources

Find Thevenin’s and Norton’s Equivalent Circuits

Thevenin’s and Norton’s equivalent circuits of a DC resistive circuit is determined. The circuit has an independent current source and a dependent voltage s

Posted byYazOctober 9, 2013August 21, 2019Posted inResistive CircuitsTags: dependent source, Norton, Norton's Equivalent Circuit, Thévenin, thevenin equivalent circuit, Thevenin_Norton8 Comments on Find Thevenin’s and Norton’s Equivalent Circuits

Solve Using Current Division Rule

A DC resistive circuit with two sources, one voltage source, one current source both independent solved using current division method.

Posted byYazOctober 2, 2013August 21, 2019Posted inResistive CircuitsTags: branch, current divider, current division rule, Current Source, Independent Sources, source_division9 Comments on Solve Using Current Division Rule

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