Tag Archives: solving linear equations

Solving Quadratic Equations II: Taking Square Roots


A quadratic equation can be solved by taking the square root of both sides of the equation. This method uses the square root property,
y^2=z \to y=\pm \sqrt{z}
Before taking the square root, the equation must be arranged with the x2 term isolated on the left- hand side of the equation and its coefficient reduced to 1. There are four steps in solving quadratic equations by this method:
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Solving Equations I: Linear Equations


In a linear equation, each term is either a constant or the product of a constant and a single variable of degree 1. It can have one or more variables. Here are some linear equations:

x+1=0
2x+4=6
-3x+1=x+4
1+5x=0
2-3x=3+2x
\frac{1}{2}x+\frac{3}{4}=\frac{1}{3}
\frac{x-1}{3}+\frac{1}{4}=\frac{5}{2}
\frac{x}{c}+b=a where  c\neq 0 is a constant
\sqrt{3}x-\sqrt{2}=\sqrt{5}

However, the following equations are not linear:
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