Superposition rule is used to solve a DC resistive circuit which has two independent voltage sources and four resistors.

# Category Archives: Electrical Circuits Problems

## AC Circuit Analysis - Sources with Different Frequencies

In AC circuit analysis, if the circuit has sources operating at different frequencies, Superposition theorem can be used to solve the circuit. Please note that AC circuits are linear and that is why Superposition theorem is valid to solve them. Problem Determine where and . Solution with AC Circuit Analysis Since sources are operating at […]

## Mesh (Current) Analysis Problem

A circuit with four meshes solved using the mesh analysis.

## Find Equivalent Impedance - AC Steady State Analysis

Determine the driving-point impedance of the network at a frequency of kHz: Solution Lets first find impedance of elements one by one: Resistor The resistor impedance is purely real and independent of frequency.

## Superposition method - Circuit with two sources

Find using superposition rule: Solution Superposition The superposition theorem states that the response (voltage or current) in any branch of a linear circuit which has more than one independent source equals the algebraic sum of the responses caused by each independent source acting alone, while all other independent sources are turned off (made zero).

## Find Thevenin's and Norton's Equivalent Circuits

Find Thevenin's and Norton's Equivalent Circuits:Suppose that , and . Solution The circuit has both independent and dependent sources. In these cases, we need to find open circuit voltage and short circuit current to determine Norton's (and also Thevenin's) equivalent circuits.

## Solve Using Current Division Rule

A DC resistive circuit with two sources, one voltage source, one current source both independent solved using current division method.

## Mesh Analysis - Supermesh

Solve the circuit and find the power of sources: , , , , , . Solution: There are three meshes in the circuit. So, we need to assign three mesh currents. It is better to have all the mesh currents loop in the same direction (usually clockwise) to prevent errors when writing out the equations.

## Solve By Source Definitions, KCL and KVL

Find the voltage across the current source and the current passing through the voltage source. Assume that , , , ,, , Solution is in series with the current source; therefore, the same current passing through it as the current source:

## Find Voltage Using Voltage Division Rule

Determine voltage across and using voltage division rule. Assume that , , , and Solution: Please note that the voltage division rule cannot be directly applied. This is to say that: