Tag: KCL

  • Solving a Circuit Using KVL and KCL 

    Solving a Circuit Using KVL and KCL 

    Use Kirchhoff’s Voltage Law (KVL) and Kirchhoff’s Current Law (KCL) to find V_x​ and I_y.

    Solving a Circuit Using KVL and KCL 

    Applying Kirchhoff’s Voltage Law (KVL)

    KVL states: The sum of all voltages in a closed loop is zero.

    Loop 1: 20V Source, 2Ω Resistor, and 5A Current Source

    We start with Loop 1 which is shown below.

    Solve Using KVl and KCL - Loop 1

    The KVL equation is:

        \[-20V - (2\Omega \cdot 2A) + V_{5A} = 0\]

    Simplify:

        \[-20V - 4V + V_{5A} = 0\]

        \[V_{5A} = 16V\]

    Loop 2: Voltage AcrossV_{5A}, 3V Source, and 7Ω Resistor

    Next, we analyze Loop 2 shown below:

    Solve Using KVl and KCL - Loop 2

    The equation is:

        \[-16V + 4V - (6\Omega \cdot I_y) = 0\]

    Simplify:

        \[-12V -6\Omega \cdot I_y = 0\]

        \[I_y = -2A\]

    KCL: Applying Kirchhoff’s Current Law (KCL)

    KCL states: The total current entering a node equals the total current leaving the node.

    At the middle node, the currents are:

        \[2A + 5A +(-2A) - I_{3\Omega} = 0\]

    Simplify:

        \[I_{3\Omega} = 5A\]

    Finding V_x

    Finally, we calculate V_x using KVL in Loop 3:

    Solve Using KVl and KCL - Loop 3

    The equation is:

        \[-16V + (3\Omega \cdot 5A) - V_x = 0\]

    Simplify:

        \[-16V + 15V - V_x = 0\]

        \[V_x = -1V\]

    Using Python to Solve the Circuit

    One powerful way to solve electrical circuits is by using the Lcapy library in Python. Lcapy is an open-source Python package designed for symbolic linear circuit analysis and signal processing.

    Below is an example of how to use Lcapy to solve the given circuit and find I_y (the current through V_2) and I_{R_1} (the current through the 2Ω resistor).

    Python Code to Solve the Circuit

    ```python
    from lcapy import Circuit
    cct = Circuit("""
    V1 1 0 20; down,
    R1 1 N_A 2; right=1.5, i=I_{R_1},
    I1 N_A 0_2 5; down, 
    W N_A 5; up=0.7, 
    R2 N_A 3 3; right=1.5, 
    V_x 0_3 3 -1; up, 
    V2 5 4 4; right=2, i=I_y,
    R4 0_4 4 6; up,
    W 0 0_2; right, 
    W 0_2 0_3; right, 
    W 0_3 0_4; right, 
    """)
    print(f"Current through R1 (I_R1): {cct.R1.i}")
    print(f"Current through V2 (I_y): {cct.V2.i}")

    which prints

    Current through R1 (I_R1): 2
    Current through V2 (I_y): -2

  • Nodal Analysis – Five-Node Circuit

    Nodal Analysis – Five-Node Circuit

    Use nodal analysis to solve the circuit shown below and determine the power of node V_{s_2}.

    I. Identify all nodes in the circuit.
    The circuit has five nodes as shown below.

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  • Solving a Simple Circuit of Three Elements

    Solving a Simple Circuit of Three Elements

    Solved the circuit to determine I_x and power absorbed or supplied by each element.

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  • Circuit Containing Only Sources

    Circuit Containing Only Sources

    We go through solving a circuit which only containes independent sources: two voltage sources and two current sources. KVL and KCL are used to determine voltages and currents.

    Determine the amount of power absorbed or supplied by each source.

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  • Superposition method – Circuit with two sources

    Superposition method – Circuit with two sources

    Find I_x using superposition rule:
    Main cuircuit to be analyzed using superposition method

    Solution

    Superposition

    The superposition theorem states that the response (voltage or current) in any branch of a linear circuit which has more than one independent source equals the algebraic sum of the responses caused by each independent source acting alone, while all other independent sources are turned off (made zero).
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  • Solve By Source Definitions, KCL and KVL

    Solve By Source Definitions, KCL and KVL

    Find the voltage across the current source and the current passing through the voltage source.
    Problem 1213
    Assume that I_1=3A, R_1=2 \Omega, R_2=3 \Omega, R_3=2 \Omega,I_1=3A, V_1=15 V,

    Solution
    R_1 is in series with the current source; therefore, the same current passing through it as the current source:
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  • Problem 1-12: Using Voltage Sources to Determine Node Voltages

    Problem 1-12: Using Voltage Sources to Determine Node Voltages

    Determine the power of  R_1, R_2 and  Vs_1. (Hint: there is no need to use nodal analysis; voltages between nodes can be easily found by the voltage sources.)
    Voltage sources can be used to fing node voltages

    Solution
    KVL around the loop
     V_{R_1}= Vs_1 = 10v \rightarrow P_{R_1}=\frac{V_{R_1}^2}{R_1}=50 W
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  • Problem 1-11: Solving a Circuit with Three Nodes by the Nodal Analysis

    Problem 1-11: Solving a Circuit with Three Nodes by the Nodal Analysis

    Solve the circuit using nodal analysis and determine the power of I_{s_1}.


    Solution
    I. Identify all nodes in the circuit. The circuit contains 3 nodes, as illustrated below.

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  • Problem 1-10: Solving by Nodal Analysis – Circuit with Four Nodes

    Problem 1-10: Solving by Nodal Analysis – Circuit with Four Nodes

    Let’s use nodal analysis to solve this circuit and determine V_a.


    Solution
    I. Identify all nodes in the circuit. There are four nodes in the circuit, as indicated below

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