A simple circuit is solved and power absorbed or supplied by each element is determined. KCL as well as Ohm’s law are used in solving the circuit. positive sign convention is used in determining element powers. It is shown and discussed how a source, here current source, can be neither absorbing or supplying power. It is also mentioned that resistors are passive elements and always absorb power/energy.
A circuit with two sources and three two port elements is studied. Some voltages and currents are given. Voltage of the voltage source is unknown. We need to analyze the circuit, find power of other elements and use the energy conservation to determine the power of the voltage source.
We go through solving a circuit which only containes independent sources: two voltage sources and two current sources. KVL and KCL are used to determine voltages and currents.
Superposition rule is used to solve a DC resistive circuit which has two independent voltage sources and four resistors.
In AC circuit analysis, if the circuit has sources operating at different frequencies, Superposition theorem can be used to solve the circuit. Please note that AC circuits are linear and that is why Superposition theorem is valid to solve them. Problem Determine where and . Solution with AC Circuit Analysis Since sources are operating at …
A circuit with four meshes solved using the mesh analysis. The circuit has two current sources, one voltage source and six resistors.
Determine the driving-point impedance of the network at a frequency of kHz: Solution Lets first find impedance of elements one by one: Resistor The resistor impedance is purely real and independent of frequency.
Finding current by using superposition method. There are two independent sources, so we need to turn them off one by one and calculate their contributions.
Thevenin’s and Norton’s equivalent circuits of a DC resistive circuit is determined. The circuit has an independent current source and a dependent voltage s
A DC resistive circuit with two sources, one voltage source, one current source both independent solved using current division method.