Thevenin’s and Norton’s equivalent circuits of a DC resistive circuit is determined. The circuit has an independent current source and a dependent voltage s
A DC resistive circuit with two sources, one voltage source, one current source both independent solved using current division method.
The mesh analysis used to solve the circuit which has a supermesh. After solving the circuit, power of sources determined.
A DC resistive circuit consisting of one voltage source and one current source and three resistors is solved using source definition, KCL and KVL.
Determine voltage across and using voltage division rule. Assume that , , , and Solution: Please note that the voltage division rule cannot be directly applied. This is to say that:
A simple circuit with two voltage sources and two resistors solved using only KVL.
Total energy stored in a circuit is calculated by finding the energy stored in each capacitor and each inductor and adding them up. The circuit has two capacitors, two inductors and two independent dc sources.
Thévenin’s Theorem is deployed to solve a simple circuit which contains two independent sources. The solution is explained step-by-step.
Thevenin’s Theorem is deployed to solve a quite simple circuit with only one independent voltage source. The solution is explained step-by-step.
A circuit with two independent and two dependent sources is solved by the superposition method. Independent sources are turned off one at a time and the contribution of the on source is calculated. Dependent sources should not be turned off.