A DC resistive circuit with two sources, one voltage source, one current source both independent solved using current division method.
Solve the circuit and find the power of sources: , , , , , . Solution: There are three meshes in the circuit. So, we need to assign three mesh currents. It is better to have all the mesh currents loop in the same direction (usually clockwise) to prevent errors when writing out the equations.
Find the voltage across the current source and the current passing through the voltage source. Assume that , , , ,, , Solution is in series with the current source; therefore, the same current passing through it as the current source:
Determine voltage across and using voltage division rule. Assume that , , , and Solution: Please note that the voltage division rule cannot be directly applied. This is to say that:
Find resistor currents using KVL. Solution: and are parallel. So the voltage across is equal to . This can be also calculated using KVL in the left hand side loop:
Total energy stored in a circuit is calculated by finding the energy stored in each capacitor and each inductor and adding them up. The circuit has two capacitors, two inductors and two independent dc sources.
Thévenin's Theorem is deployed to solve a simple circuit which contains two independent sources. The solution is explained step-by-step.
Thevenin's Theorem is deployed to solve a quite simple circuit with only one independent voltage source. The solution is explained step-by-step.
A circuit with two independent and two dependent sources is solved by the superposition method. Independent sources are turned off one at a time and the contribution of the on source is calculated. Dependent sources should not be turned off.
A circuit with two voltage sources and two current sources is solved by the superposition method. The contribution of each source is calculated individually and the response is found by adding the contributions.