A simple circuit is solved and power absorbed or supplied by each element is determined. KCL as well as Ohm’s law are used in solving the circuit. positive sign convention is used in determining element powers. It is shown and discussed how a source, here current source, can be neither absorbing or supplying power. It is also mentioned that resistors are passive elements and always absorb power/energy.
Superposition rule is used to solve a DC resistive circuit which has two independent voltage sources and four resistors.
A circuit with four meshes solved using the mesh analysis. The circuit has two current sources, one voltage source and six resistors.
Finding current by using superposition method. There are two independent sources, so we need to turn them off one by one and calculate their contributions.
Thevenin’s and Norton’s equivalent circuits of a DC resistive circuit is determined. The circuit has an independent current source and a dependent voltage s
A DC resistive circuit with two sources, one voltage source, one current source both independent solved using current division method.
The mesh analysis used to solve the circuit which has a supermesh. After solving the circuit, power of sources determined.
A DC resistive circuit consisting of one voltage source and one current source and three resistors is solved using source definition, KCL and KVL.
Determine voltage across and using voltage division rule. Assume that , , , and Solution: Please note that the voltage division rule cannot be directly applied. This is to say that:
A simple circuit with two voltage sources and two resistors solved using only KVL.